if xy = 180 and HCF(x,y) = 3, then find LCM(x,y). Class 10 mathematics c...

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Class 10 Maths CBSE Previous Year Question:-
If xy = 180 and HCF(x,y) = 3, then find LCM(x,y). Class 10 mathematics chapter 1 real numbers important question cbse board exam previous year question
Video Solution:-

Solution
Given that xy = 180 and HCF(x,y) = 3

we are required to find LCM(x,y)

Using formula

HCF ✕ LCM = Product of two numbers

3 ✕ LCM(x,y) = xy

3 ✕ LCM(x,y) = 180

LCM(x,y) = 180
3
So, LCM(x,y) = 60
                                                


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